[12 piece bucket]

UPP,
I'm glad you posted that. No, I'm not including the left wrist at all in the equation at this point- just to keep things simple. Does it have some affect- sure but let's agree that as Matthew says it's minimal- in fact- don't even include it in the equation.

I'm saying that the number 7 is the representation of the shoulder line - and the primary lever /. So, we are looking at the primary lever as if it was one single piece - one 2x4.

Now, per one of my previous posts- you took the pencil lead and put it between the "shoulders" i.e. in the middle of the top line of the 7 and then rotated it- the corner of the 7 where they both meet represents the golfer's lead shoulder at address- from the face on view. The slanting leg of the 7 represents the primary lever - from the face on view. Now, like the golfer swinging - the left shoulder of the 7 moves up but the end of the primary lever system i.e. clubhead does not begin to move up until it passes where- ever the shoulder is. In fact if you have that pencil lead in the middle of the top line and you rotate the 7 clockwise- you can see that the shoulder goes down- while the clubhead goes up. That's the same thing that I am saying is happening on the downswing- at some point halfway down- the shoulder begins to move up in relation to the ground- as it orbits around it's own circle while the clubhead is still moving down.

Here is what started this whole thing- Matthew posted the following:
Actually, no it doesn't. This would be true if the left shoulder was stationary, however in the golf stroke the left shoulder is moving in its own little orbit that contains an upwards direction and this brings the low point backwards somewhat.

I see the left shoulder starting to move up - when you're hands are say half way down on the down swing. I guess I should ask Matthew when do you see the left shoulder moving up? I get the feeling from his quote and posts that maybe he sees it just moving up slightly before where low point would be for a stationary shoulder.

Doesn't the angle in your 7 example change? The accumulator angle seeks it's inline condition right?